Base | Representation |
---|---|
bin | 101101010001100111111… |
… | …100000111011000101011 |
3 | 102000102210212002220222201 |
4 | 231101213330013120223 |
5 | 401433420313300233 |
6 | 10341151143401031 |
7 | 440532626535004 |
oct | 55214774073053 |
9 | 12012725086881 |
10 | 3111300134443 |
11 | a9a5498a6066 |
12 | 422ba8153177 |
13 | 1975184b1017 |
14 | aa832a341ab |
15 | 55deaa5677d |
hex | 2d467f0762b |
3111300134443 has 2 divisors, whose sum is σ = 3111300134444. Its totient is φ = 3111300134442.
The previous prime is 3111300134441. The next prime is 3111300134461. The reversal of 3111300134443 is 3444310031113.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3111300134443 - 21 = 3111300134441 is a prime.
Together with 3111300134441, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (3111300134441) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1555650067221 + 1555650067222.
It is an arithmetic number, because the mean of its divisors is an integer number (1555650067222).
Almost surely, 23111300134443 is an apocalyptic number.
3111300134443 is a deficient number, since it is larger than the sum of its proper divisors (1).
3111300134443 is an equidigital number, since it uses as much as digits as its factorization.
3111300134443 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 3111300134443 its reverse (3444310031113), we get a palindrome (6555610165556).
The spelling of 3111300134443 in words is "three trillion, one hundred eleven billion, three hundred million, one hundred thirty-four thousand, four hundred forty-three".
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