3111310013 has 4 divisors (see below), whose sum is σ = 3555782880. Its totient is φ = 2666837148.

The previous prime is 3111309997. The next prime is 3111310067. The reversal of 3111310013 is 3100131113.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3100131113 = 131 ⋅23665123.

It is a cyclic number.

It is not a de Polignac number, because 3111310013 - 2⁴ = 3111309997 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 3111310013.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3111310613) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 222236423 + ... + 222236436.

It is an arithmetic number, because the mean of its divisors is an integer number (888945720).

Almost surely, 2^3111310013 is an apocalyptic number.

It is an amenable number.

3111310013 is a deficient number, since it is larger than the sum of its proper divisors (444472867).

3111310013 is an equidigital number, since it uses as much as digits as its factorization.

3111310013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 444472866.

The product of its (nonzero) digits is 27, while the sum is 14.

The square root of 3111310013 is about 55779.1180729850. The cubic root of 3111310013 is about 1459.8708231555.

Adding to 3111310013 its reverse (3100131113), we get a palindrome (6211441126).

The spelling of 3111310013 in words is "three billion, one hundred eleven million, three hundred ten thousand, thirteen".