Base | Representation |
---|---|
bin | 1001000011100001101… |
… | …10101001101011110111 |
3 | 1002202002020220102122222 |
4 | 10201300312221223313 |
5 | 20044144020120043 |
6 | 354533121312555 |
7 | 31323055014635 |
oct | 4416066515367 |
9 | 1082066812588 |
10 | 311131020023 |
11 | 10aa4a3933aa |
12 | 5037119575b |
13 | 23454c3b0a5 |
14 | 110b759a355 |
15 | 815e9cdd68 |
hex | 4870da9af7 |
311131020023 has 2 divisors, whose sum is σ = 311131020024. Its totient is φ = 311131020022.
The previous prime is 311131020007. The next prime is 311131020029. The reversal of 311131020023 is 320020131113.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 311131020023 - 24 = 311131020007 is a prime.
It is a Sophie Germain prime.
It is a junction number, because it is equal to n+sod(n) for n = 311131019983 and 311131020010.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (311131020029) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155565510011 + 155565510012.
It is an arithmetic number, because the mean of its divisors is an integer number (155565510012).
Almost surely, 2311131020023 is an apocalyptic number.
311131020023 is a deficient number, since it is larger than the sum of its proper divisors (1).
311131020023 is an equidigital number, since it uses as much as digits as its factorization.
311131020023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 108, while the sum is 17.
Adding to 311131020023 its reverse (320020131113), we get a palindrome (631151151136).
The spelling of 311131020023 in words is "three hundred eleven billion, one hundred thirty-one million, twenty thousand, twenty-three".
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