Base | Representation |
---|---|
bin | 1011100101110010… |
… | …1101011100001000 |
3 | 22000211110222110220 |
4 | 2321130231130020 |
5 | 22332443423422 |
6 | 1232422110040 |
7 | 140046464610 |
oct | 27134553410 |
9 | 8024428426 |
10 | 3111311112 |
11 | 13572880a8 |
12 | 729b7b320 |
13 | 3a77885c0 |
14 | 2172dda40 |
15 | 13322ee5c |
hex | b972d708 |
3111311112 has 128 divisors (see below), whose sum is σ = 9666908160. Its totient is φ = 812540160.
The previous prime is 3111311101. The next prime is 3111311143. The reversal of 3111311112 is 2111131113.
3111311112 is digitally balanced in base 2 and base 4, because in such bases it contains all the possibile digits an equal number of times.
It is a nude number because it is divisible by every one of its digits.
It is a junction number, because it is equal to n+sod(n) for n = 3111311091 and 3111311100.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 218037 + ... + 231867.
It is an arithmetic number, because the mean of its divisors is an integer number (75522720).
Almost surely, 23111311112 is an apocalyptic number.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 3111311112, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (4833454080).
3111311112 is an abundant number, since it is smaller than the sum of its proper divisors (6555597048).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
3111311112 is a wasteful number, since it uses less digits than its factorization.
3111311112 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13963 (or 13959 counting only the distinct ones).
The product of its digits is 18, while the sum is 15.
The square root of 3111311112 is about 55779.1279243410. The cubic root of 3111311112 is about 1459.8709950442.
Adding to 3111311112 its reverse (2111131113), we get a palindrome (5222442225).
It can be divided in two parts, 311131111 and 2, that added together give a palindrome (311131113).
The spelling of 3111311112 in words is "three billion, one hundred eleven million, three hundred eleven thousand, one hundred twelve".
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