Base | Representation |
---|---|
bin | 1001000011100001110… |
… | …11100101001010011111 |
3 | 1002202002100100002020020 |
4 | 10201300323211022133 |
5 | 20044144332442343 |
6 | 354533205123223 |
7 | 31323102006165 |
oct | 4416073451237 |
9 | 1082070302206 |
10 | 311132312223 |
11 | 10aa50096237 |
12 | 503716b9513 |
13 | 234552a12c5 |
14 | 110b7815235 |
15 | 815eb86b83 |
hex | 4870ee529f |
311132312223 has 32 divisors (see below), whose sum is σ = 441796239360. Its totient is φ = 194089720320.
The previous prime is 311132312213. The next prime is 311132312269. The reversal of 311132312223 is 322213231113.
311132312223 is digitally balanced in base 4, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 311132312223 - 25 = 311132312191 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 311132312193 and 311132312202.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (311132312203) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 6596761 + ... + 6643757.
It is an arithmetic number, because the mean of its divisors is an integer number (13806132480).
Almost surely, 2311132312223 is an apocalyptic number.
311132312223 is a deficient number, since it is larger than the sum of its proper divisors (130663927137).
311132312223 is a wasteful number, since it uses less digits than its factorization.
311132312223 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 47767.
The product of its digits is 1296, while the sum is 24.
Adding to 311132312223 its reverse (322213231113), we get a palindrome (633345543336).
The spelling of 311132312223 in words is "three hundred eleven billion, one hundred thirty-two million, three hundred twelve thousand, two hundred twenty-three".
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