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311132322202213 is a prime number
BaseRepresentation
bin100011010111110010010001…
…1100010110000001001100101
31111210121221220111011121100201
41012233210203202300021211
5311240042443440432323
63021420114323510501
7122351365663062541
oct10657444342601145
91453557814147321
10311132322202213
1190155527753446
122aa8b641228431
131047b86284a435
1456b8c55a44a21
1525e83ebb868ad
hex11af9238b0265

311132322202213 has 2 divisors, whose sum is σ = 311132322202214. Its totient is φ = 311132322202212.

The previous prime is 311132322202183. The next prime is 311132322202237. The reversal of 311132322202213 is 312202223231113.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 301236220520964 + 9896101681249 = 17356158^2 + 3145807^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-311132322202213 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (311132325202213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155566161101106 + 155566161101107.

It is an arithmetic number, because the mean of its divisors is an integer number (155566161101107).

Almost surely, 2311132322202213 is an apocalyptic number.

It is an amenable number.

311132322202213 is a deficient number, since it is larger than the sum of its proper divisors (1).

311132322202213 is an equidigital number, since it uses as much as digits as its factorization.

311132322202213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 311132322202213 its reverse (312202223231113), we get a palindrome (623334545433326).

The spelling of 311132322202213 in words is "three hundred eleven trillion, one hundred thirty-two billion, three hundred twenty-two million, two hundred two thousand, two hundred thirteen".