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3111334112 = 2597229191
BaseRepresentation
bin1011100101110011…
…0011000011100000
322000211112011000202
42321130303003200
522333000142422
61232422404332
7140046621635
oct27134630340
98024464022
103111334112
1113572a3407
12729b906a8
133a7795c03
1421730818c
15133236b92
hexb97330e0

3111334112 has 12 divisors (see below), whose sum is σ = 6125439096. Its totient is φ = 1555667040.

The previous prime is 3111334043. The next prime is 3111334117. The reversal of 3111334112 is 2114331113.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3111334117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 48614564 + ... + 48614627.

It is an arithmetic number, because the mean of its divisors is an integer number (510453258).

Almost surely, 23111334112 is an apocalyptic number.

3111334112 is a gapful number since it is divisible by the number (32) formed by its first and last digit.

It is an amenable number.

3111334112 is a deficient number, since it is larger than the sum of its proper divisors (3014104984).

3111334112 is an equidigital number, since it uses as much as digits as its factorization.

3111334112 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 97229201 (or 97229193 counting only the distinct ones).

The product of its digits is 216, while the sum is 20.

The square root of 3111334112 is about 55779.3340942683. The cubic root of 3111334112 is about 1459.8745923434.

Adding to 3111334112 its reverse (2114331113), we get a palindrome (5225665225).

Subtracting from 3111334112 its reverse (2114331113), we obtain a cube (997002999 = 9993).

The spelling of 3111334112 in words is "three billion, one hundred eleven million, three hundred thirty-four thousand, one hundred twelve".

Divisors: 1 2 4 8 16 32 97229191 194458382 388916764 777833528 1555667056 3111334112