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3111402023 is a prime number
BaseRepresentation
bin1011100101110100…
…0011101000100111
322000211122121011222
42321131003220213
522333004331043
61232424050555
7140050323632
oct27135035047
98024577158
103111402023
11135733a434
1272a003a5b
133a77baab2
14217324c19
1513324bd68
hexb9743a27

3111402023 has 2 divisors, whose sum is σ = 3111402024. Its totient is φ = 3111402022.

The previous prime is 3111402001. The next prime is 3111402029. The reversal of 3111402023 is 3202041113.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 3111402023 - 28 = 3111401767 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 3111401992 and 3111402010.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3111402029) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1555701011 + 1555701012.

It is an arithmetic number, because the mean of its divisors is an integer number (1555701012).

Almost surely, 23111402023 is an apocalyptic number.

3111402023 is a deficient number, since it is larger than the sum of its proper divisors (1).

3111402023 is an equidigital number, since it uses as much as digits as its factorization.

3111402023 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 3111402023 is about 55779.9428379055. The cubic root of 3111402023 is about 1459.8852138130.

Adding to 3111402023 its reverse (3202041113), we get a palindrome (6313443136).

The spelling of 3111402023 in words is "three billion, one hundred eleven million, four hundred two thousand, twenty-three".