Base | Representation |
---|---|
bin | 1001000011100010111… |
… | …01000111111111111111 |
3 | 1002202002221212211120012 |
4 | 10201301131013333333 |
5 | 20044204110340123 |
6 | 354534121413435 |
7 | 31323236522063 |
oct | 4416135077777 |
9 | 1082087784505 |
10 | 311141105663 |
11 | 10aa55051943 |
12 | 5037463a27b |
13 | 2345705c91b |
14 | 110b8a63aa3 |
15 | 8160822378 |
hex | 4871747fff |
311141105663 has 4 divisors (see below), whose sum is σ = 311246974920. Its totient is φ = 311035236408.
The previous prime is 311141105659. The next prime is 311141105669. The reversal of 311141105663 is 366501141113.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 366501141113 = 71 ⋅5161987903.
It is a cyclic number.
It is not a de Polignac number, because 311141105663 - 22 = 311141105659 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (311141105669) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 52930220 + ... + 52936097.
It is an arithmetic number, because the mean of its divisors is an integer number (77811743730).
Almost surely, 2311141105663 is an apocalyptic number.
311141105663 is a deficient number, since it is larger than the sum of its proper divisors (105869257).
311141105663 is a wasteful number, since it uses less digits than its factorization.
311141105663 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 105869256.
The product of its (nonzero) digits is 6480, while the sum is 32.
Adding to 311141105663 its reverse (366501141113), we get a palindrome (677642246776).
The spelling of 311141105663 in words is "three hundred eleven billion, one hundred forty-one million, one hundred five thousand, six hundred sixty-three".
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