Base | Representation |
---|---|
bin | 1110001001100010101001… |
… | …01001010001111001110111 |
3 | 11002011111002112022121120021 |
4 | 13010301110221101321313 |
5 | 13034233301234341412 |
6 | 150101352123150011 |
7 | 6360631653335665 |
oct | 704612451217167 |
9 | 132144075277507 |
10 | 31114163199607 |
11 | 9a06495a88594 |
12 | 35a6172375307 |
13 | 144908c5972b7 |
14 | 797d0d88dc35 |
15 | 38e53dd98607 |
hex | 1c4c54a51e77 |
31114163199607 has 2 divisors, whose sum is σ = 31114163199608. Its totient is φ = 31114163199606.
The previous prime is 31114163199601. The next prime is 31114163199733. The reversal of 31114163199607 is 70699136141113.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-31114163199607 is a prime.
It is a super-2 number, since 2×311141631996072 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31114163199601) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15557081599803 + 15557081599804.
It is an arithmetic number, because the mean of its divisors is an integer number (15557081599804).
Almost surely, 231114163199607 is an apocalyptic number.
31114163199607 is a deficient number, since it is larger than the sum of its proper divisors (1).
31114163199607 is an equidigital number, since it uses as much as digits as its factorization.
31114163199607 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 734832, while the sum is 52.
The spelling of 31114163199607 in words is "thirty-one trillion, one hundred fourteen billion, one hundred sixty-three million, one hundred ninety-nine thousand, six hundred seven".
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