Base | Representation |
---|---|
bin | 11100111110100011… |
… | …101011111100000001 |
3 | 2222022102001220002111 |
4 | 130332203223330001 |
5 | 1002210231012343 |
6 | 22143235415321 |
7 | 2151020205115 |
oct | 347643537401 |
9 | 88272056074 |
10 | 31114313473 |
11 | 12217245261 |
12 | 6044154541 |
13 | 2c1b1b7a99 |
14 | 1712431745 |
15 | c2188ac9d |
hex | 73e8ebf01 |
31114313473 has 2 divisors, whose sum is σ = 31114313474. Its totient is φ = 31114313472.
The previous prime is 31114313471. The next prime is 31114313567. The reversal of 31114313473 is 37431341113.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 15670783489 + 15443529984 = 125183^2 + 124272^2 .
It is a cyclic number.
It is not a de Polignac number, because 31114313473 - 21 = 31114313471 is a prime.
It is a super-2 number, since 2×311143134732 (a number of 22 digits) contains 22 as substring.
Together with 31114313471, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (31114313471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15557156736 + 15557156737.
It is an arithmetic number, because the mean of its divisors is an integer number (15557156737).
Almost surely, 231114313473 is an apocalyptic number.
It is an amenable number.
31114313473 is a deficient number, since it is larger than the sum of its proper divisors (1).
31114313473 is an equidigital number, since it uses as much as digits as its factorization.
31114313473 is an evil number, because the sum of its binary digits is even.
The product of its digits is 9072, while the sum is 31.
Adding to 31114313473 its reverse (37431341113), we get a palindrome (68545654586).
The spelling of 31114313473 in words is "thirty-one billion, one hundred fourteen million, three hundred thirteen thousand, four hundred seventy-three".
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