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31114325505121 is a prime number
BaseRepresentation
bin1110001001100010111100…
…10100011011010001100001
311002011111111211201120212121
413010301132110123101201
513034234114312130441
6150101420202024241
76360635664036625
oct704613624332141
9132144454646777
1031114325505121
119a06569665081
1235a61b87a8081
1314490b70b4271
14797d2725d185
1538e54d258dd1
hex1c4c5e51b461

31114325505121 has 2 divisors, whose sum is σ = 31114325505122. Its totient is φ = 31114325505120.

The previous prime is 31114325505103. The next prime is 31114325505157. The reversal of 31114325505121 is 12150552341113.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 28630108205521 + 2484217299600 = 5350711^2 + 1576140^2 .

It is a cyclic number.

It is not a de Polignac number, because 31114325505121 - 213 = 31114325496929 is a prime.

It is not a weakly prime, because it can be changed into another prime (31114325505821) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15557162752560 + 15557162752561.

It is an arithmetic number, because the mean of its divisors is an integer number (15557162752561).

Almost surely, 231114325505121 is an apocalyptic number.

It is an amenable number.

31114325505121 is a deficient number, since it is larger than the sum of its proper divisors (1).

31114325505121 is an equidigital number, since it uses as much as digits as its factorization.

31114325505121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18000, while the sum is 34.

Adding to 31114325505121 its reverse (12150552341113), we get a palindrome (43264877846234).

The spelling of 31114325505121 in words is "thirty-one trillion, one hundred fourteen billion, three hundred twenty-five million, five hundred five thousand, one hundred twenty-one".