Base | Representation |
---|---|
bin | 1110001001100100011011… |
… | …01101010010010100101101 |
3 | 11002011120120020202010002011 |
4 | 13010302031231102110231 |
5 | 13034242231330114323 |
6 | 150102031122401221 |
7 | 6360664456601356 |
oct | 704621555222455 |
9 | 132146506663064 |
10 | 31115120551213 |
11 | 9a06937421a66 |
12 | 35a639ab00211 |
13 | 14491b2a2133a |
14 | 797da0a98d2d |
15 | 38e597e5320d |
hex | 1c4c8db5252d |
31115120551213 has 2 divisors, whose sum is σ = 31115120551214. Its totient is φ = 31115120551212.
The previous prime is 31115120551187. The next prime is 31115120551241. The reversal of 31115120551213 is 31215502151113.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 25047042108804 + 6068078442409 = 5004702^2 + 2463347^2 .
It is a cyclic number.
It is not a de Polignac number, because 31115120551213 - 241 = 28916097295661 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31115120551313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15557560275606 + 15557560275607.
It is an arithmetic number, because the mean of its divisors is an integer number (15557560275607).
Almost surely, 231115120551213 is an apocalyptic number.
It is an amenable number.
31115120551213 is a deficient number, since it is larger than the sum of its proper divisors (1).
31115120551213 is an equidigital number, since it uses as much as digits as its factorization.
31115120551213 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4500, while the sum is 31.
The spelling of 31115120551213 in words is "thirty-one trillion, one hundred fifteen billion, one hundred twenty million, five hundred fifty-one thousand, two hundred thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •