Base | Representation |
---|---|
bin | 101101010010000110111… |
… | …011111111101000101001 |
3 | 102000111011002200210212102 |
4 | 231102012323333220221 |
5 | 401441001432241033 |
6 | 10341314522223145 |
7 | 440551543146416 |
oct | 55220673775051 |
9 | 12014132623772 |
10 | 3111820196393 |
11 | a9a796415327 |
12 | 423112354ab5 |
13 | 19759c16b79c |
14 | aa881b2d10d |
15 | 55e2b533de8 |
hex | 2d486effa29 |
3111820196393 has 2 divisors, whose sum is σ = 3111820196394. Its totient is φ = 3111820196392.
The previous prime is 3111820196339. The next prime is 3111820196477. The reversal of 3111820196393 is 3936910281113.
Together with previous prime (3111820196339) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2002573105129 + 1109247091264 = 1415123^2 + 1053208^2 .
It is a cyclic number.
It is not a de Polignac number, because 3111820196393 - 216 = 3111820130857 is a prime.
It is not a weakly prime, because it can be changed into another prime (3111820196893) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1555910098196 + 1555910098197.
It is an arithmetic number, because the mean of its divisors is an integer number (1555910098197).
Almost surely, 23111820196393 is an apocalyptic number.
It is an amenable number.
3111820196393 is a deficient number, since it is larger than the sum of its proper divisors (1).
3111820196393 is an equidigital number, since it uses as much as digits as its factorization.
3111820196393 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 209952, while the sum is 47.
The spelling of 3111820196393 in words is "three trillion, one hundred eleven billion, eight hundred twenty million, one hundred ninety-six thousand, three hundred ninety-three".
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