Base | Representation |
---|---|
bin | 101101010010010000011… |
… | …000110100101100010011 |
3 | 102000111120011001002201202 |
4 | 231102100120310230103 |
5 | 401441313024424231 |
6 | 10341342344421415 |
7 | 440555506626131 |
oct | 55222030645423 |
9 | 12014504032652 |
10 | 3111978748691 |
11 | a9a867968a8a |
12 | 42315747786b |
13 | 1975c5c73307 |
14 | aa898c02751 |
15 | 55e3a4025cb |
hex | 2d490634b13 |
3111978748691 has 2 divisors, whose sum is σ = 3111978748692. Its totient is φ = 3111978748690.
The previous prime is 3111978748663. The next prime is 3111978748693. The reversal of 3111978748691 is 1968478791113.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3111978748691 - 210 = 3111978747667 is a prime.
Together with 3111978748693, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (3111978748693) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1555989374345 + 1555989374346.
It is an arithmetic number, because the mean of its divisors is an integer number (1555989374346).
Almost surely, 23111978748691 is an apocalyptic number.
3111978748691 is a deficient number, since it is larger than the sum of its proper divisors (1).
3111978748691 is an equidigital number, since it uses as much as digits as its factorization.
3111978748691 is an evil number, because the sum of its binary digits is even.
The product of its digits is 18289152, while the sum is 65.
The spelling of 3111978748691 in words is "three trillion, one hundred eleven billion, nine hundred seventy-eight million, seven hundred forty-eight thousand, six hundred ninety-one".
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