Base | Representation |
---|---|
bin | 1110001001101101100010… |
… | …01001011110100010101011 |
3 | 11002012001012000022111100112 |
4 | 13010312301021132202223 |
5 | 13034332240042024042 |
6 | 150104200230524535 |
7 | 6361226601302216 |
oct | 704666111364253 |
9 | 132161160274315 |
10 | 31120010111147 |
11 | 9a08a16457791 |
12 | 35a732450674b |
13 | 14497b1a22479 |
14 | 79830620c77d |
15 | 38e782341982 |
hex | 1c4db125e8ab |
31120010111147 has 2 divisors, whose sum is σ = 31120010111148. Its totient is φ = 31120010111146.
The previous prime is 31120010111111. The next prime is 31120010111149. The reversal of 31120010111147 is 74111101002113.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 31120010111147 - 214 = 31120010094763 is a prime.
Together with 31120010111149, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (31120010111149) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15560005055573 + 15560005055574.
It is an arithmetic number, because the mean of its divisors is an integer number (15560005055574).
Almost surely, 231120010111147 is an apocalyptic number.
31120010111147 is a deficient number, since it is larger than the sum of its proper divisors (1).
31120010111147 is an equidigital number, since it uses as much as digits as its factorization.
31120010111147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 168, while the sum is 23.
The spelling of 31120010111147 in words is "thirty-one trillion, one hundred twenty billion, ten million, one hundred eleven thousand, one hundred forty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.082 sec. • engine limits •