Base | Representation |
---|---|
bin | 1001000011101001111… |
… | …10001101011000100001 |
3 | 1002202021001220120110012 |
4 | 10201310332031120201 |
5 | 20044314212010423 |
6 | 354544030214305 |
7 | 31324554201524 |
oct | 4416476153041 |
9 | 1082231816405 |
10 | 311200110113 |
11 | 10aa85392852 |
12 | 50390354395 |
13 | 2346634b6b9 |
14 | 110c2822bbb |
15 | 8165aca078 |
hex | 4874f8d621 |
311200110113 has 2 divisors, whose sum is σ = 311200110114. Its totient is φ = 311200110112.
The previous prime is 311200110103. The next prime is 311200110157. The reversal of 311200110113 is 311011002113.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 308583583009 + 2616527104 = 555503^2 + 51152^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-311200110113 is a prime.
It is not a weakly prime, because it can be changed into another prime (311200110103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155600055056 + 155600055057.
It is an arithmetic number, because the mean of its divisors is an integer number (155600055057).
Almost surely, 2311200110113 is an apocalyptic number.
It is an amenable number.
311200110113 is a deficient number, since it is larger than the sum of its proper divisors (1).
311200110113 is an equidigital number, since it uses as much as digits as its factorization.
311200110113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18, while the sum is 14.
Adding to 311200110113 its reverse (311011002113), we get a palindrome (622211112226).
The spelling of 311200110113 in words is "three hundred eleven billion, two hundred million, one hundred ten thousand, one hundred thirteen".
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