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3112001201120 = 255731417329947
BaseRepresentation
bin101101010010010001101…
…110011110001111100000
3102000111121201021210200012
4231102101232132033200
5401441334301413440
610341344505544052
7440556201521120
oct55222156361740
912014551253605
103112001201120
11a9a879603909
12423162aa5028
131975ca804a86
14aa89bba8c80
1555e3c389e65
hex2d491b9e3e0

3112001201120 has 384 divisors, whose sum is σ = 9007009062912. Its totient is φ = 993536409600.

The previous prime is 3112001200969. The next prime is 3112001201129. The reversal of 3112001201120 is 211021002113.

3112001201120 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (14).

It is a junction number, because it is equal to n+sod(n) for n = 3112001201095 and 3112001201104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3112001201129) by changing a digit.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 103901987 + ... + 103931933.

It is an arithmetic number, because the mean of its divisors is an integer number (23455752768).

Almost surely, 23112001201120 is an apocalyptic number.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 3112001201120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (4503504531456).

3112001201120 is an abundant number, since it is smaller than the sum of its proper divisors (5895007861792).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

3112001201120 is a wasteful number, since it uses less digits than its factorization.

3112001201120 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 30114 (or 30106 counting only the distinct ones).

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 3112001201120 its reverse (211021002113), we get a palindrome (3323022203233).

The spelling of 3112001201120 in words is "three trillion, one hundred twelve billion, one million, two hundred one thousand, one hundred twenty".