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311202022013 is a prime number
BaseRepresentation
bin1001000011101010001…
…01100000001001111101
31002202021012111201002022
410201311011200021331
520044320204201023
6354544135205525
731324606353551
oct4416505401175
91082235451068
10311202022013
1110aa86479233
1250390b168a5
132346686a9bc
14110c2b9d861
158165d567c8
hex487516027d

311202022013 has 2 divisors, whose sum is σ = 311202022014. Its totient is φ = 311202022012.

The previous prime is 311202022009. The next prime is 311202022063. The reversal of 311202022013 is 310220202113.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 258289601284 + 52912420729 = 508222^2 + 230027^2 .

It is a cyclic number.

It is not a de Polignac number, because 311202022013 - 22 = 311202022009 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 311202021982 and 311202022000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (311202022063) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155601011006 + 155601011007.

It is an arithmetic number, because the mean of its divisors is an integer number (155601011007).

Almost surely, 2311202022013 is an apocalyptic number.

It is an amenable number.

311202022013 is a deficient number, since it is larger than the sum of its proper divisors (1).

311202022013 is an equidigital number, since it uses as much as digits as its factorization.

311202022013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 311202022013 its reverse (310220202113), we get a palindrome (621422224126).

The spelling of 311202022013 in words is "three hundred eleven billion, two hundred two million, twenty-two thousand, thirteen".