Base | Representation |
---|---|
bin | 101101010010010111110… |
… | …000001011110101110100 |
3 | 102000111212202112211112221 |
4 | 231102113300023311310 |
5 | 401442041143011312 |
6 | 10341402521052124 |
7 | 440561540124655 |
oct | 55222760136564 |
9 | 12014782484487 |
10 | 3112102313332 |
11 | a9a920694a21 |
12 | 423190927044 |
13 | 19761574789c |
14 | aa8ab3a952c |
15 | 55e461ae207 |
hex | 2d497c0bd74 |
3112102313332 has 6 divisors (see below), whose sum is σ = 5446179048338. Its totient is φ = 1556051156664.
The previous prime is 3112102313239. The next prime is 3112102313423. The reversal of 3112102313332 is 2333132012113.
It can be written as a sum of positive squares in only one way, i.e., 2995135577316 + 116966736016 = 1730646^2 + 342004^2 .
It is a junction number, because it is equal to n+sod(n) for n = 3112102313297 and 3112102313306.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 389012789163 + ... + 389012789170.
Almost surely, 23112102313332 is an apocalyptic number.
It is an amenable number.
3112102313332 is a deficient number, since it is larger than the sum of its proper divisors (2334076735006).
3112102313332 is a wasteful number, since it uses less digits than its factorization.
3112102313332 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 778025578337 (or 778025578335 counting only the distinct ones).
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 3112102313332 its reverse (2333132012113), we get a palindrome (5445234325445).
The spelling of 3112102313332 in words is "three trillion, one hundred twelve billion, one hundred two million, three hundred thirteen thousand, three hundred thirty-two".
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