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3112102313332 = 22778025578333
BaseRepresentation
bin101101010010010111110…
…000001011110101110100
3102000111212202112211112221
4231102113300023311310
5401442041143011312
610341402521052124
7440561540124655
oct55222760136564
912014782484487
103112102313332
11a9a920694a21
12423190927044
1319761574789c
14aa8ab3a952c
1555e461ae207
hex2d497c0bd74

3112102313332 has 6 divisors (see below), whose sum is σ = 5446179048338. Its totient is φ = 1556051156664.

The previous prime is 3112102313239. The next prime is 3112102313423. The reversal of 3112102313332 is 2333132012113.

It can be written as a sum of positive squares in only one way, i.e., 2995135577316 + 116966736016 = 1730646^2 + 342004^2 .

It is a junction number, because it is equal to n+sod(n) for n = 3112102313297 and 3112102313306.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 389012789163 + ... + 389012789170.

Almost surely, 23112102313332 is an apocalyptic number.

It is an amenable number.

3112102313332 is a deficient number, since it is larger than the sum of its proper divisors (2334076735006).

3112102313332 is a wasteful number, since it uses less digits than its factorization.

3112102313332 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 778025578337 (or 778025578335 counting only the distinct ones).

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 3112102313332 its reverse (2333132012113), we get a palindrome (5445234325445).

The spelling of 3112102313332 in words is "three trillion, one hundred twelve billion, one hundred two million, three hundred thirteen thousand, three hundred thirty-two".

Divisors: 1 2 4 778025578333 1556051156666 3112102313332