311211310013 has 2 divisors, whose sum is σ = 311211310014. Its totient is φ = 311211310012.

The previous prime is 311211309973. The next prime is 311211310051. The reversal of 311211310013 is 310013112113.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 310964600164 + 246709849 = 557642^2 + 15707^2 .

It is a cyclic number.

It is not a de Polignac number, because 311211310013 - 2¹⁸ = 311211047869 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 311211309973 and 311211310000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (311211310073) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155605655006 + 155605655007.

It is an arithmetic number, because the mean of its divisors is an integer number (155605655007).

Almost surely, 2^311211310013 is an apocalyptic number.

It is an amenable number.

311211310013 is a deficient number, since it is larger than the sum of its proper divisors (1).

311211310013 is an equidigital number, since it uses as much as digits as its factorization.

311211310013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 311211310013 its reverse (310013112113), we get a palindrome (621224422126).

The spelling of 311211310013 in words is "three hundred eleven billion, two hundred eleven million, three hundred ten thousand, thirteen".