Base | Representation |
---|---|
bin | 100011011000010111000100… |
… | …0110101110100100011000111 |
3 | 1111210220111211202101000221211 |
4 | 1012300232020311310203013 |
5 | 311242341301231023421 |
6 | 3021520302314552251 |
7 | 122360163621526654 |
oct | 10660561065644307 |
9 | 1453814752330854 |
10 | 311211331111111 |
11 | 90185a91171072 |
12 | 2aaa2a11138687 |
13 | 104861445440c2 |
14 | 56bc9ccd10c2b |
15 | 25ea4c31339e1 |
hex | 11b0b88d748c7 |
311211331111111 has 2 divisors, whose sum is σ = 311211331111112. Its totient is φ = 311211331111110.
The previous prime is 311211331111081. The next prime is 311211331111117. The reversal of 311211331111111 is 111111133112113.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 311211331111111 - 27 = 311211331110983 is a prime.
It is a super-2 number, since 2×3112113311111112 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (311211331111117) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155605665555555 + 155605665555556.
It is an arithmetic number, because the mean of its divisors is an integer number (155605665555556).
Almost surely, 2311211331111111 is an apocalyptic number.
311211331111111 is a deficient number, since it is larger than the sum of its proper divisors (1).
311211331111111 is an equidigital number, since it uses as much as digits as its factorization.
311211331111111 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 54, while the sum is 22.
Adding to 311211331111111 its reverse (111111133112113), we get a palindrome (422322464223224).
The spelling of 311211331111111 in words is "three hundred eleven trillion, two hundred eleven billion, three hundred thirty-one million, one hundred eleven thousand, one hundred eleven".
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