Base | Representation |
---|---|
bin | 101101010010011000011… |
… | …010001001001000101111 |
3 | 102000111220112020122022020 |
4 | 231102120122021020233 |
5 | 401442102001443203 |
6 | 10341403552521223 |
7 | 440562032454642 |
oct | 55223032111057 |
9 | 12014815218266 |
10 | 3112113312303 |
11 | a9a926917686 |
12 | 423194550213 |
13 | 197617ac9058 |
14 | aa8aca2da59 |
15 | 55e47133153 |
hex | 2d49868922f |
3112113312303 has 16 divisors (see below), whose sum is σ = 4395191381856. Its totient is φ = 1951978705920.
The previous prime is 3112113312289. The next prime is 3112113312331. The reversal of 3112113312303 is 3032133112113.
It is not a de Polignac number, because 3112113312303 - 25 = 3112113312271 is a prime.
It is a super-2 number, since 2×31121133123032 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3112113316303) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 11107828 + ... + 11384553.
It is an arithmetic number, because the mean of its divisors is an integer number (274699461366).
Almost surely, 23112113312303 is an apocalyptic number.
3112113312303 is a deficient number, since it is larger than the sum of its proper divisors (1283078069553).
3112113312303 is a wasteful number, since it uses less digits than its factorization.
3112113312303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 22495114.
The product of its (nonzero) digits is 972, while the sum is 24.
Adding to 3112113312303 its reverse (3032133112113), we get a palindrome (6144246424416).
The spelling of 3112113312303 in words is "three trillion, one hundred twelve billion, one hundred thirteen million, three hundred twelve thousand, three hundred three".
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