Base | Representation |
---|---|
bin | 101101010010011010000… |
… | …000111000000111111011 |
3 | 102000111222101220212220011 |
4 | 231102122000320013323 |
5 | 401442130400242301 |
6 | 10341410354042351 |
7 | 440562510412261 |
oct | 55223200700773 |
9 | 12014871825804 |
10 | 3112140243451 |
11 | a9a940041428 |
12 | 4231a15793b7 |
13 | 197620568245 |
14 | aa8b2440431 |
15 | 55e496a2a51 |
hex | 2d49a0381fb |
3112140243451 has 2 divisors, whose sum is σ = 3112140243452. Its totient is φ = 3112140243450.
The previous prime is 3112140243419. The next prime is 3112140243469. The reversal of 3112140243451 is 1543420412113.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3112140243451 - 25 = 3112140243419 is a prime.
It is not a weakly prime, because it can be changed into another prime (3112140243551) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1556070121725 + 1556070121726.
It is an arithmetic number, because the mean of its divisors is an integer number (1556070121726).
Almost surely, 23112140243451 is an apocalyptic number.
3112140243451 is a deficient number, since it is larger than the sum of its proper divisors (1).
3112140243451 is an equidigital number, since it uses as much as digits as its factorization.
3112140243451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11520, while the sum is 31.
Adding to 3112140243451 its reverse (1543420412113), we get a palindrome (4655560655564).
The spelling of 3112140243451 in words is "three trillion, one hundred twelve billion, one hundred forty million, two hundred forty-three thousand, four hundred fifty-one".
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