Base | Representation |
---|---|
bin | 100011011000011000011100… |
… | …1110100111010110110100100 |
3 | 1111210220210111200200200012200 |
4 | 1012300300321310322312210 |
5 | 311242413341403121040 |
6 | 3021521513110014500 |
7 | 122360330325446253 |
oct | 10660607164726644 |
9 | 1453823450620180 |
10 | 311214300442020 |
11 | 90187275294358 |
12 | 2aaa34bb647430 |
13 | 104864c877ac41 |
14 | 56bcbd141279a |
15 | 25ea5e8b6a630 |
hex | 11b0c39d3ada4 |
311214300442020 has 72 divisors (see below), whose sum is σ = 944021462267520. Its totient is φ = 82990062454080.
The previous prime is 311214300442013. The next prime is 311214300442033. The reversal of 311214300442020 is 20244003412113.
311214300442020 is a `hidden beast` number, since 3 + 1 + 1 + 21 + 430 + 0 + 4 + 4 + 202 + 0 = 666.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 32373685 + ... + 40871555.
It is an arithmetic number, because the mean of its divisors is an integer number (13111409198160).
Almost surely, 2311214300442020 is an apocalyptic number.
311214300442020 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
It is an amenable number.
311214300442020 is an abundant number, since it is smaller than the sum of its proper divisors (632807161825500).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
311214300442020 is a wasteful number, since it uses less digits than its factorization.
311214300442020 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8701345 (or 8701340 counting only the distinct ones).
The product of its (nonzero) digits is 4608, while the sum is 27.
Adding to 311214300442020 its reverse (20244003412113), we get a palindrome (331458303854133).
The spelling of 311214300442020 in words is "three hundred eleven trillion, two hundred fourteen billion, three hundred million, four hundred forty-two thousand, twenty".
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