Base | Representation |
---|---|
bin | 1110001001110000001011… |
… | …11110111100001000010001 |
3 | 11002012011212012111200020010 |
4 | 13010320011332330020101 |
5 | 13034343143423141423 |
6 | 150104553353105133 |
7 | 6361310063202552 |
oct | 704700576741021 |
9 | 132164765450203 |
10 | 31121433412113 |
11 | 9a09586910880 |
12 | 35a76610b81a9 |
13 | 144997a86b9a5 |
14 | 7983dd268329 |
15 | 38e81728a693 |
hex | 1c4e05fbc211 |
31121433412113 has 64 divisors (see below), whose sum is σ = 46609758987264. Its totient is φ = 18304846560000.
The previous prime is 31121433412103. The next prime is 31121433412141.
It is a happy number.
31121433412113 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 31121433412113 - 25 = 31121433412081 is a prime.
It is not an unprimeable number, because it can be changed into a prime (31121433412103) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 2499506538 + ... + 2499518988.
It is an arithmetic number, because the mean of its divisors is an integer number (728277484176).
Almost surely, 231121433412113 is an apocalyptic number.
31121433412113 is a gapful number since it is divisible by the number (33) formed by its first and last digit.
It is an amenable number.
31121433412113 is a deficient number, since it is larger than the sum of its proper divisors (15488325575151).
31121433412113 is a wasteful number, since it uses less digits than its factorization.
31121433412113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 17566.
The product of its digits is 5184, while the sum is 30.
It can be divided in two parts, 3112143 and 3412113, that added together give a palindrome (6524256).
The spelling of 31121433412113 in words is "thirty-one trillion, one hundred twenty-one billion, four hundred thirty-three million, four hundred twelve thousand, one hundred thirteen".
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