Base | Representation |
---|---|
bin | 100011011000011011001010… |
… | …0110000101010111010010011 |
3 | 1111210221100112100010210000122 |
4 | 1012300312110300222322103 |
5 | 311243012301440201344 |
6 | 3021524314433140455 |
7 | 122360624503533422 |
oct | 10660662460527223 |
9 | 1453840470123018 |
10 | 311220121022099 |
11 | 90189791909313 |
12 | 2aaa46649ba72b |
13 | 10486c15616b73 |
14 | 56bd1c44792b9 |
15 | 25ea839b61aee |
hex | 11b0d94c2ae93 |
311220121022099 has 2 divisors, whose sum is σ = 311220121022100. Its totient is φ = 311220121022098.
The previous prime is 311220121022089. The next prime is 311220121022101. The reversal of 311220121022099 is 990220121022113.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 311220121022099 - 224 = 311220104244883 is a prime.
Together with 311220121022101, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (311220121022089) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155610060511049 + 155610060511050.
It is an arithmetic number, because the mean of its divisors is an integer number (155610060511050).
Almost surely, 2311220121022099 is an apocalyptic number.
311220121022099 is a deficient number, since it is larger than the sum of its proper divisors (1).
311220121022099 is an equidigital number, since it uses as much as digits as its factorization.
311220121022099 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7776, while the sum is 35.
The spelling of 311220121022099 in words is "three hundred eleven trillion, two hundred twenty billion, one hundred twenty-one million, twenty-two thousand, ninety-nine".
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