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311221113200981 is a prime number
BaseRepresentation
bin100011011000011011100111…
…1111001100010000101010101
31111210221110002111002200120122
41012300313033321202011111
5311243021314434412411
63021525001115041325
7122360661212111264
oct10660671771420525
91453843074080518
10311221113200981
119018a15097aa65
122aaa48a1140245
1310487043046169
1456bd27a14c5db
1525ea896cea9db
hex11b0dcfe62155

311221113200981 has 2 divisors, whose sum is σ = 311221113200982. Its totient is φ = 311221113200980.

The previous prime is 311221113200951. The next prime is 311221113201049. The reversal of 311221113200981 is 189002311122113.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 181175234218225 + 130045878982756 = 13460135^2 + 11403766^2 .

It is a cyclic number.

It is not a de Polignac number, because 311221113200981 - 230 = 311220039459157 is a prime.

It is a super-3 number, since 3×3112211132009813 (a number of 44 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (311221113200951) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155610556600490 + 155610556600491.

It is an arithmetic number, because the mean of its divisors is an integer number (155610556600491).

Almost surely, 2311221113200981 is an apocalyptic number.

It is an amenable number.

311221113200981 is a deficient number, since it is larger than the sum of its proper divisors (1).

311221113200981 is an equidigital number, since it uses as much as digits as its factorization.

311221113200981 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5184, while the sum is 35.

The spelling of 311221113200981 in words is "three hundred eleven trillion, two hundred twenty-one billion, one hundred thirteen million, two hundred thousand, nine hundred eighty-one".