Base | Representation |
---|---|
bin | 1001000011101100011… |
… | …10011001011101011110 |
3 | 1002202022112110112211100 |
4 | 10201312032121131132 |
5 | 20044340102143402 |
6 | 354550100533530 |
7 | 31325230652310 |
oct | 4416616313536 |
9 | 1082275415740 |
10 | 311221131102 |
11 | 10aa96240172 |
12 | 503973b12a6 |
13 | 2346a7cb75b |
14 | 110c55357b0 |
15 | 816787d71c |
hex | 487639975e |
311221131102 has 24 divisors (see below), whose sum is σ = 770642801136. Its totient is φ = 88920323136.
The previous prime is 311221131101. The next prime is 311221131107. The reversal of 311221131102 is 201131122113.
311221131102 is a `hidden beast` number, since 311 + 221 + 1 + 31 + 102 = 666.
It is a super-3 number, since 3×3112211311023 (a number of 35 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (311221131101) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1235004363 + ... + 1235004614.
It is an arithmetic number, because the mean of its divisors is an integer number (32110116714).
Almost surely, 2311221131102 is an apocalyptic number.
311221131102 is an abundant number, since it is smaller than the sum of its proper divisors (459421670034).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
311221131102 is a wasteful number, since it uses less digits than its factorization.
311221131102 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2470008992 (or 2470008989 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 18.
Adding to 311221131102 its reverse (201131122113), we get a palindrome (512352253215).
The spelling of 311221131102 in words is "three hundred eleven billion, two hundred twenty-one million, one hundred thirty-one thousand, one hundred two".
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