Base | Representation |
---|---|
bin | 1110001001110001011101… |
… | …11101111000010101100011 |
3 | 11002012020122010022202212221 |
4 | 13010320232331320111203 |
5 | 13034401100434002131 |
6 | 150105145514331511 |
7 | 6361333112461036 |
oct | 704705675702543 |
9 | 132166563282787 |
10 | 31122121000291 |
11 | 9a098a9a52a72 |
12 | 35a7813429b97 |
13 | 1449a5a1537b9 |
14 | 7984666d101d |
15 | 38e85780a411 |
hex | 1c4e2ef78563 |
31122121000291 has 2 divisors, whose sum is σ = 31122121000292. Its totient is φ = 31122121000290.
The previous prime is 31122121000219. The next prime is 31122121000447. The reversal of 31122121000291 is 19200012122113.
Together with previous prime (31122121000219) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 31122121000291 - 229 = 31121584129379 is a prime.
It is a super-3 number, since 3×311221210002913 (a number of 41 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (31122121000211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15561060500145 + 15561060500146.
It is an arithmetic number, because the mean of its divisors is an integer number (15561060500146).
Almost surely, 231122121000291 is an apocalyptic number.
31122121000291 is a deficient number, since it is larger than the sum of its proper divisors (1).
31122121000291 is an equidigital number, since it uses as much as digits as its factorization.
31122121000291 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 25.
The spelling of 31122121000291 in words is "thirty-one trillion, one hundred twenty-two billion, one hundred twenty-one million, two hundred ninety-one", and thus it is an aban number.
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