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3112220203133 is a prime number
BaseRepresentation
bin101101010010011110110…
…001111001100001111101
3102000112011222101020221212
4231102132301321201331
5401442311333000013
610341422331534205
7440564501150006
oct55223661714175
912015158336855
103112220203133
11a9a981195308
124232042ba365
13197633cb3172
14aa8bccd61ad
1555e516e96a8
hex2d49ec7987d

3112220203133 has 2 divisors, whose sum is σ = 3112220203134. Its totient is φ = 3112220203132.

The previous prime is 3112220203121. The next prime is 3112220203151. The reversal of 3112220203133 is 3313020222113.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2989918223044 + 122301980089 = 1729138^2 + 349717^2 .

It is a cyclic number.

It is not a de Polignac number, because 3112220203133 - 28 = 3112220202877 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 3112220203099 and 3112220203108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3112220203933) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1556110101566 + 1556110101567.

It is an arithmetic number, because the mean of its divisors is an integer number (1556110101567).

Almost surely, 23112220203133 is an apocalyptic number.

It is an amenable number.

3112220203133 is a deficient number, since it is larger than the sum of its proper divisors (1).

3112220203133 is an equidigital number, since it uses as much as digits as its factorization.

3112220203133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 3112220203133 its reverse (3313020222113), we get a palindrome (6425240425246).

The spelling of 3112220203133 in words is "three trillion, one hundred twelve billion, two hundred twenty million, two hundred three thousand, one hundred thirty-three".