Base | Representation |
---|---|
bin | 101101010010011111011… |
… | …110111100110110011010 |
3 | 102000112012210121021100010 |
4 | 231102133132330312122 |
5 | 401442322343410320 |
6 | 10341423433022350 |
7 | 440565003425505 |
oct | 55223736746632 |
9 | 12015183537303 |
10 | 3112232013210 |
11 | a9a987921401 |
12 | 4232082549b6 |
13 | 197636589888 |
14 | aa8c06cc13c |
15 | 55e5277dae0 |
hex | 2d49f7bcd9a |
3112232013210 has 16 divisors (see below), whose sum is σ = 7469356831776. Its totient is φ = 829928536848.
The previous prime is 3112232013173. The next prime is 3112232013281. The reversal of 3112232013210 is 123102322113.
It is a super-2 number, since 2×31122320132102 (a number of 26 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 51870533524 + ... + 51870533583.
It is an arithmetic number, because the mean of its divisors is an integer number (466834801986).
Almost surely, 23112232013210 is an apocalyptic number.
3112232013210 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
3112232013210 is an abundant number, since it is smaller than the sum of its proper divisors (4357124818566).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
3112232013210 is a wasteful number, since it uses less digits than its factorization.
3112232013210 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 103741067117.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 3112232013210 its reverse (123102322113), we get a palindrome (3235334335323).
The spelling of 3112232013210 in words is "three trillion, one hundred twelve billion, two hundred thirty-two million, thirteen thousand, two hundred ten".
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