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311225421440503 is a prime number
BaseRepresentation
bin100011011000011101101000…
…0101100001010010111110111
31111210221212012201210221011101
41012300323100230022113313
5311243104130342044003
63021530552415350531
7122361203034412333
oct10660732054122767
91453855181727141
10311225421440503
1190190a61856099
122aaa56a3b22447
131048757b78bb0b
1456bd5683bc7c3
1525eaa4a15b11d
hex11b0ed0b0a5f7

311225421440503 has 2 divisors, whose sum is σ = 311225421440504. Its totient is φ = 311225421440502.

The previous prime is 311225421440489. The next prime is 311225421440551. The reversal of 311225421440503 is 305044124522113.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 311225421440503 - 25 = 311225421440471 is a prime.

It is a super-2 number, since 2×3112254214405032 (a number of 30 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (311225422440503) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155612710720251 + 155612710720252.

It is an arithmetic number, because the mean of its divisors is an integer number (155612710720252).

Almost surely, 2311225421440503 is an apocalyptic number.

311225421440503 is a deficient number, since it is larger than the sum of its proper divisors (1).

311225421440503 is an equidigital number, since it uses as much as digits as its factorization.

311225421440503 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 115200, while the sum is 37.

Adding to 311225421440503 its reverse (305044124522113), we get a palindrome (616269545962616).

The spelling of 311225421440503 in words is "three hundred eleven trillion, two hundred twenty-five billion, four hundred twenty-one million, four hundred forty thousand, five hundred three".