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311225504453 is a prime number
BaseRepresentation
bin1001000011101100111…
…11000101001011000101
31002202022211200201221022
410201312133011023011
520044342212120303
6354550334400525
731325313065513
oct4416637051305
91082284621838
10311225504453
1110aa98757a06
1250398960145
132346b6a0236
14110c5d534b3
158167e44438
hex48767c52c5

311225504453 has 2 divisors, whose sum is σ = 311225504454. Its totient is φ = 311225504452.

The previous prime is 311225504441. The next prime is 311225504497. The reversal of 311225504453 is 354405522113.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 303785061889 + 7440442564 = 551167^2 + 86258^2 .

It is a cyclic number.

It is not a de Polignac number, because 311225504453 - 210 = 311225503429 is a prime.

It is a super-2 number, since 2×3112255044532 (a number of 24 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (311225104453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155612752226 + 155612752227.

It is an arithmetic number, because the mean of its divisors is an integer number (155612752227).

Almost surely, 2311225504453 is an apocalyptic number.

It is an amenable number.

311225504453 is a deficient number, since it is larger than the sum of its proper divisors (1).

311225504453 is an equidigital number, since it uses as much as digits as its factorization.

311225504453 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72000, while the sum is 35.

The spelling of 311225504453 in words is "three hundred eleven billion, two hundred twenty-five million, five hundred four thousand, four hundred fifty-three".