Base | Representation |
---|---|
bin | 1110001001110011001001… |
… | …01011101110010000111011 |
3 | 11002012022221221002222100021 |
4 | 13010321210223232100323 |
5 | 13034404422141210412 |
6 | 150105415150351311 |
7 | 6361364334565642 |
oct | 704714453562073 |
9 | 132168857088307 |
10 | 31123022210107 |
11 | 9a0a221731273 |
12 | 35a7a251bb537 |
13 | 1449b71a81a49 |
14 | 798510284359 |
15 | 38e8ab9c5607 |
hex | 1c4e64aee43b |
31123022210107 has 2 divisors, whose sum is σ = 31123022210108. Its totient is φ = 31123022210106.
The previous prime is 31123022210101. The next prime is 31123022210129. The reversal of 31123022210107 is 70101222032113.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 31123022210107 - 215 = 31123022177339 is a prime.
It is a super-2 number, since 2×311230222101072 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (31123022210101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15561511105053 + 15561511105054.
It is an arithmetic number, because the mean of its divisors is an integer number (15561511105054).
Almost surely, 231123022210107 is an apocalyptic number.
31123022210107 is a deficient number, since it is larger than the sum of its proper divisors (1).
31123022210107 is an equidigital number, since it uses as much as digits as its factorization.
31123022210107 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1008, while the sum is 25.
The spelling of 31123022210107 in words is "thirty-one trillion, one hundred twenty-three billion, twenty-two million, two hundred ten thousand, one hundred seven".
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