Base | Representation |
---|---|
bin | 101101010010100100001… |
… | …000111010101100101111 |
3 | 102000112102020120200020211 |
4 | 231102210020322230233 |
5 | 401443002342421221 |
6 | 10341435303123251 |
7 | 440566642360654 |
oct | 55224410725457 |
9 | 12015366520224 |
10 | 3112310123311 |
11 | a9aa17a21704 |
12 | 42322a443527 |
13 | 19764980797c |
14 | aa8cac21c2b |
15 | 55e5955c6e1 |
hex | 2d4a423ab2f |
3112310123311 has 2 divisors, whose sum is σ = 3112310123312. Its totient is φ = 3112310123310.
The previous prime is 3112310123269. The next prime is 3112310123443. The reversal of 3112310123311 is 1133210132113.
3112310123311 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is an emirp because it is prime and its reverse (1133210132113) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3112310123311 - 231 = 3110162639663 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3112310123911) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1556155061655 + 1556155061656.
It is an arithmetic number, because the mean of its divisors is an integer number (1556155061656).
Almost surely, 23112310123311 is an apocalyptic number.
3112310123311 is a deficient number, since it is larger than the sum of its proper divisors (1).
3112310123311 is an equidigital number, since it uses as much as digits as its factorization.
3112310123311 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 324, while the sum is 22.
Adding to 3112310123311 its reverse (1133210132113), we get a palindrome (4245520255424).
The spelling of 3112310123311 in words is "three trillion, one hundred twelve billion, three hundred ten million, one hundred twenty-three thousand, three hundred eleven".
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