3112311320223 has 8 divisors (see below), whose sum is σ = 4742569630848. Its totient is φ = 1778463611544.

The previous prime is 3112311320219. The next prime is 3112311320257. The reversal of 3112311320223 is 3220231132113.

3112311320223 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 3112311320223 - 2² = 3112311320219 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 3112311320193 and 3112311320202.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3112311320273) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 74102650461 + ... + 74102650502.

It is an arithmetic number, because the mean of its divisors is an integer number (592821203856).

Almost surely, 2^{3112311320223} is an apocalyptic number.

3112311320223 is a deficient number, since it is larger than the sum of its proper divisors (1630258310625).

3112311320223 is a wasteful number, since it uses less digits than its factorization.

3112311320223 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 148205300973.

The product of its (nonzero) digits is 1296, while the sum is 24.

Adding to 3112311320223 its reverse (3220231132113), we get a palindrome (6332542452336).

The spelling of 3112311320223 in words is "three trillion, one hundred twelve billion, three hundred eleven million, three hundred twenty thousand, two hundred twenty-three".