Base | Representation |
---|---|
bin | 1110001001110011101110… |
… | …00110111011000010101111 |
3 | 11002012100202110202220102110 |
4 | 13010321313012323002233 |
5 | 13034411040310031343 |
6 | 150105505552055103 |
7 | 6361405110221526 |
oct | 704716706730257 |
9 | 132170673686373 |
10 | 31123331330223 |
11 | 9a0a370174840 |
12 | 35a7ab0834493 |
13 | 1449bc0b23a62 |
14 | 79853d34d4bd |
15 | 38e8c8bd6833 |
hex | 1c4e771bb0af |
31123331330223 has 32 divisors (see below), whose sum is σ = 45304233004800. Its totient is φ = 18848490105600.
The previous prime is 31123331330219. The next prime is 31123331330251. The reversal of 31123331330223 is 32203313332113.
It is not a de Polignac number, because 31123331330223 - 22 = 31123331330219 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (31123331330293) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 362239593 + ... + 362325501.
It is an arithmetic number, because the mean of its divisors is an integer number (1415757281400).
Almost surely, 231123331330223 is an apocalyptic number.
31123331330223 is a gapful number since it is divisible by the number (33) formed by its first and last digit.
31123331330223 is a deficient number, since it is larger than the sum of its proper divisors (14180901674577).
31123331330223 is a wasteful number, since it uses less digits than its factorization.
31123331330223 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 94023.
The product of its (nonzero) digits is 17496, while the sum is 30.
Adding to 31123331330223 its reverse (32203313332113), we get a palindrome (63326644662336).
The spelling of 31123331330223 in words is "thirty-one trillion, one hundred twenty-three billion, three hundred thirty-one million, three hundred thirty thousand, two hundred twenty-three".
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