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311240221131414 = 2394718354765943
BaseRepresentation
bin100011011000100100100001…
…0110100100000001010010110
31111211000021102011001010102210
41012301021002310200022112
5311243324433102201124
63021541441140214250
7122362235552616261
oct10661110264401226
91454007364033383
10311240221131414
11901972668a3a03
122aaa853439a386
1310488a99972c83
1456c016db7dcd8
1525eb1145a4a29
hex11b1242d20296

311240221131414 has 16 divisors (see below), whose sum is σ = 622481110820352. Its totient is φ = 103746628950888.

The previous prime is 311240221131397. The next prime is 311240221131421. The reversal of 311240221131414 is 414131122042113.

It is a Curzon number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 21699874 + ... + 33066069.

It is an arithmetic number, because the mean of its divisors is an integer number (38905069426272).

Almost surely, 2311240221131414 is an apocalyptic number.

311240221131414 is an abundant number, since it is smaller than the sum of its proper divisors (311240889688938).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

311240221131414 is a wasteful number, since it uses less digits than its factorization.

311240221131414 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 55713131.

The product of its (nonzero) digits is 4608, while the sum is 30.

Adding to 311240221131414 its reverse (414131122042113), we get a palindrome (725371343173527).

The spelling of 311240221131414 in words is "three hundred eleven trillion, two hundred forty billion, two hundred twenty-one million, one hundred thirty-one thousand, four hundred fourteen".

Divisors: 1 2 3 6 947183 1894366 2841549 5683098 54765943 109531886 164297829 328595658 51873370188569 103746740377138 155620110565707 311240221131414