Base | Representation |
---|---|
bin | 100011011000100100100001… |
… | …0110100100000001010010110 |
3 | 1111211000021102011001010102210 |
4 | 1012301021002310200022112 |
5 | 311243324433102201124 |
6 | 3021541441140214250 |
7 | 122362235552616261 |
oct | 10661110264401226 |
9 | 1454007364033383 |
10 | 311240221131414 |
11 | 901972668a3a03 |
12 | 2aaa853439a386 |
13 | 10488a99972c83 |
14 | 56c016db7dcd8 |
15 | 25eb1145a4a29 |
hex | 11b1242d20296 |
311240221131414 has 16 divisors (see below), whose sum is σ = 622481110820352. Its totient is φ = 103746628950888.
The previous prime is 311240221131397. The next prime is 311240221131421. The reversal of 311240221131414 is 414131122042113.
It is a Curzon number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 21699874 + ... + 33066069.
It is an arithmetic number, because the mean of its divisors is an integer number (38905069426272).
Almost surely, 2311240221131414 is an apocalyptic number.
311240221131414 is an abundant number, since it is smaller than the sum of its proper divisors (311240889688938).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
311240221131414 is a wasteful number, since it uses less digits than its factorization.
311240221131414 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 55713131.
The product of its (nonzero) digits is 4608, while the sum is 30.
Adding to 311240221131414 its reverse (414131122042113), we get a palindrome (725371343173527).
The spelling of 311240221131414 in words is "three hundred eleven trillion, two hundred forty billion, two hundred twenty-one million, one hundred thirty-one thousand, four hundred fourteen".
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