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311255214050413 is a prime number
BaseRepresentation
bin100011011000101011100000…
…0011101111100110001101101
31111211001201010000212022211001
41012301113000131330301231
5311244101134244103123
63021552401002400301
7122363306235414343
oct10661270035746155
91454051100768731
10311255214050413
11901a265aa19956
122aaab419500091
131048a318bacc89
1456c0b9307d993
1525eb6e096b0ad
hex11b15c077cc6d

311255214050413 has 2 divisors, whose sum is σ = 311255214050414. Its totient is φ = 311255214050412.

The previous prime is 311255214050377. The next prime is 311255214050419. The reversal of 311255214050413 is 314050412552113.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 305100909911044 + 6154304139369 = 17467138^2 + 2480787^2 .

It is a cyclic number.

It is not a de Polignac number, because 311255214050413 - 237 = 311117775096941 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (311255214050419) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155627607025206 + 155627607025207.

It is an arithmetic number, because the mean of its divisors is an integer number (155627607025207).

Almost surely, 2311255214050413 is an apocalyptic number.

It is an amenable number.

311255214050413 is a deficient number, since it is larger than the sum of its proper divisors (1).

311255214050413 is an equidigital number, since it uses as much as digits as its factorization.

311255214050413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72000, while the sum is 37.

The spelling of 311255214050413 in words is "three hundred eleven trillion, two hundred fifty-five billion, two hundred fourteen million, fifty thousand, four hundred thirteen".