Search a number
-
+
311257099507681 is a prime number
BaseRepresentation
bin100011011000101100011000…
…0110110011001011111100001
31111211001212222102200110221201
41012301120300312121133201
5311244114014433221211
63021553312034321201
7122363404041504325
oct10661306066313741
91454055872613851
10311257099507681
11901a34382418a8
122aaab864a29201
131048a5596c1372
1456c0cd163d985
1525eb7a12550c1
hex11b1630d997e1

311257099507681 has 2 divisors, whose sum is σ = 311257099507682. Its totient is φ = 311257099507680.

The previous prime is 311257099507481. The next prime is 311257099507693. The reversal of 311257099507681 is 186705990752113.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 305375310450081 + 5881789057600 = 17474991^2 + 2425240^2 .

It is a cyclic number.

It is not a de Polignac number, because 311257099507681 - 29 = 311257099507169 is a prime.

It is a super-2 number, since 2×3112570995076812 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (311257099507481) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155628549753840 + 155628549753841.

It is an arithmetic number, because the mean of its divisors is an integer number (155628549753841).

Almost surely, 2311257099507681 is an apocalyptic number.

It is an amenable number.

311257099507681 is a deficient number, since it is larger than the sum of its proper divisors (1).

311257099507681 is an equidigital number, since it uses as much as digits as its factorization.

311257099507681 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 28576800, while the sum is 64.

The spelling of 311257099507681 in words is "three hundred eleven trillion, two hundred fifty-seven billion, ninety-nine million, five hundred seven thousand, six hundred eighty-one".