Base | Representation |
---|---|
bin | 100011011000101100011000… |
… | …0110110011001011111100001 |
3 | 1111211001212222102200110221201 |
4 | 1012301120300312121133201 |
5 | 311244114014433221211 |
6 | 3021553312034321201 |
7 | 122363404041504325 |
oct | 10661306066313741 |
9 | 1454055872613851 |
10 | 311257099507681 |
11 | 901a34382418a8 |
12 | 2aaab864a29201 |
13 | 1048a5596c1372 |
14 | 56c0cd163d985 |
15 | 25eb7a12550c1 |
hex | 11b1630d997e1 |
311257099507681 has 2 divisors, whose sum is σ = 311257099507682. Its totient is φ = 311257099507680.
The previous prime is 311257099507481. The next prime is 311257099507693. The reversal of 311257099507681 is 186705990752113.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 305375310450081 + 5881789057600 = 17474991^2 + 2425240^2 .
It is a cyclic number.
It is not a de Polignac number, because 311257099507681 - 29 = 311257099507169 is a prime.
It is a super-2 number, since 2×3112570995076812 (a number of 30 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (311257099507481) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155628549753840 + 155628549753841.
It is an arithmetic number, because the mean of its divisors is an integer number (155628549753841).
Almost surely, 2311257099507681 is an apocalyptic number.
It is an amenable number.
311257099507681 is a deficient number, since it is larger than the sum of its proper divisors (1).
311257099507681 is an equidigital number, since it uses as much as digits as its factorization.
311257099507681 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 28576800, while the sum is 64.
The spelling of 311257099507681 in words is "three hundred eleven trillion, two hundred fifty-seven billion, ninety-nine million, five hundred seven thousand, six hundred eighty-one".
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