311300001201151 has 2 divisors, whose sum is σ = 311300001201152. Its totient is φ = 311300001201150.

The previous prime is 311300001201067. The next prime is 311300001201169. The reversal of 311300001201151 is 151102100003113.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 311300001201151 - 2¹⁵ = 311300001168383 is a prime.

It is a super-2 number, since 2×311300001201151² (a number of 30 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (311300001201451) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155650000600575 + 155650000600576.

It is an arithmetic number, because the mean of its divisors is an integer number (155650000600576).

Almost surely, 2^{311300001201151} is an apocalyptic number.

311300001201151 is a deficient number, since it is larger than the sum of its proper divisors (1).

311300001201151 is an equidigital number, since it uses as much as digits as its factorization.

311300001201151 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 90, while the sum is 19.

Adding to 311300001201151 its reverse (151102100003113), we get a palindrome (462402101204264).

The spelling of 311300001201151 in words is "three hundred eleven trillion, three hundred billion, one million, two hundred one thousand, one hundred fifty-one".