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31130000147 is a prime number
BaseRepresentation
bin11100111111011111…
…100001101100010011
32222100111120212011102
4130333133201230103
51002223240001042
622144555535015
72151300430631
oct347737415423
988314525142
1031130000147
1112225089954
12604945a46b
132c2151ab3c
141714556351
15c22e38b32
hex73f7e1b13

31130000147 has 2 divisors, whose sum is σ = 31130000148. Its totient is φ = 31130000146.

The previous prime is 31129999981. The next prime is 31130000171. The reversal of 31130000147 is 74100003113.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-31130000147 is a prime.

It is not a weakly prime, because it can be changed into another prime (31130000747) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15565000073 + 15565000074.

It is an arithmetic number, because the mean of its divisors is an integer number (15565000074).

Almost surely, 231130000147 is an apocalyptic number.

31130000147 is a deficient number, since it is larger than the sum of its proper divisors (1).

31130000147 is an equidigital number, since it uses as much as digits as its factorization.

31130000147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 252, while the sum is 20.

The spelling of 31130000147 in words is "thirty-one billion, one hundred thirty million, one hundred forty-seven", and thus it is an aban number.