Base | Representation |
---|---|
bin | 100011011001000000011010… |
… | …0000000000000001111100111 |
3 | 1111211012222222100111222012001 |
4 | 1012302000310000000033213 |
5 | 311300320102104432221 |
6 | 3022025143111510131 |
7 | 122366455505065402 |
oct | 10662006400001747 |
9 | 1454188870458161 |
10 | 311300102030311 |
11 | 9020a6a50235a9 |
12 | 2aab8066388347 |
13 | 1049162082c424 |
14 | 56c30108acd39 |
15 | 25ec96b62d391 |
hex | 11b20340003e7 |
311300102030311 has 2 divisors, whose sum is σ = 311300102030312. Its totient is φ = 311300102030310.
The previous prime is 311300102030221. The next prime is 311300102030341. The reversal of 311300102030311 is 113030201003113.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 311300102030311 - 235 = 311265742291943 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (311300102030341) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155650051015155 + 155650051015156.
It is an arithmetic number, because the mean of its divisors is an integer number (155650051015156).
Almost surely, 2311300102030311 is an apocalyptic number.
311300102030311 is a deficient number, since it is larger than the sum of its proper divisors (1).
311300102030311 is an equidigital number, since it uses as much as digits as its factorization.
311300102030311 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 311300102030311 its reverse (113030201003113), we get a palindrome (424330303033424).
The spelling of 311300102030311 in words is "three hundred eleven trillion, three hundred billion, one hundred two million, thirty thousand, three hundred eleven".
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