Base | Representation |
---|---|
bin | 1110001010000000001100… |
… | …11001001010111011111110 |
3 | 11002020000001022220220220010 |
4 | 13011000012121022323332 |
5 | 13040013300214114402 |
6 | 150112534412404050 |
7 | 6362033111660466 |
oct | 705000631127376 |
9 | 132200038826803 |
10 | 31130030223102 |
11 | 9a12198559148 |
12 | 35a9260176626 |
13 | 144a71a931cb5 |
14 | 7989b6cc8ba6 |
15 | 38eb6bd73a6c |
hex | 1c500664aefe |
31130030223102 has 32 divisors (see below), whose sum is σ = 64498838021280. Its totient is φ = 10004568022400.
The previous prime is 31130030223079. The next prime is 31130030223161. The reversal of 31130030223102 is 20132203003113.
It is a super-3 number, since 3×311300302231023 (a number of 41 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 127487313 + ... + 127731260.
It is an arithmetic number, because the mean of its divisors is an integer number (2015588688165).
Almost surely, 231130030223102 is an apocalyptic number.
31130030223102 is an abundant number, since it is smaller than the sum of its proper divisors (33368807798178).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
31130030223102 is a wasteful number, since it uses less digits than its factorization.
31130030223102 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 255219308.
The product of its (nonzero) digits is 648, while the sum is 21.
Adding to 31130030223102 its reverse (20132203003113), we get a palindrome (51262233226215).
The spelling of 31130030223102 in words is "thirty-one trillion, one hundred thirty billion, thirty million, two hundred twenty-three thousand, one hundred two".
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