Base | Representation |
---|---|
bin | 100011011001000001011000… |
… | …1000011000111111000000111 |
3 | 1111211020012101120012212120101 |
4 | 1012302002301003013320013 |
5 | 311300333401200000012 |
6 | 3022030131214344531 |
7 | 122366561501405206 |
oct | 10662026103077007 |
9 | 1454205346185511 |
10 | 311302200000007 |
11 | 902105812a5257 |
12 | 2aab8550abb147 |
13 | 10491896389108 |
14 | 56c316d38b23d |
15 | 25eca408e3d57 |
hex | 11b20b10c7e07 |
311302200000007 has 2 divisors, whose sum is σ = 311302200000008. Its totient is φ = 311302200000006.
The previous prime is 311302199999939. The next prime is 311302200000023. The reversal of 311302200000007 is 700000002203113.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 311302200000007 - 231 = 311300052516359 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 311302200000007.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (311302200003007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155651100000003 + 155651100000004.
It is an arithmetic number, because the mean of its divisors is an integer number (155651100000004).
Almost surely, 2311302200000007 is an apocalyptic number.
311302200000007 is a deficient number, since it is larger than the sum of its proper divisors (1).
311302200000007 is an equidigital number, since it uses as much as digits as its factorization.
311302200000007 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 252, while the sum is 19.
The spelling of 311302200000007 in words is "three hundred eleven trillion, three hundred two billion, two hundred million, seven", and thus it is an aban number.
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •