Base | Representation |
---|---|
bin | 101101010011001111000… |
… | …110110110011111111111 |
3 | 102000121021111001010001122 |
4 | 231103033012312133333 |
5 | 402000441414031421 |
6 | 10342035014101155 |
7 | 440623544631302 |
oct | 55231706663777 |
9 | 12017244033048 |
10 | 3113031002111 |
11 | aa0257931608 |
12 | 4233ab94a7bb |
13 | 197732c77484 |
14 | aa958872b39 |
15 | 55e9c9a62ab |
hex | 2d4cf1b67ff |
3113031002111 has 2 divisors, whose sum is σ = 3113031002112. Its totient is φ = 3113031002110.
The previous prime is 3113031002089. The next prime is 3113031002143. The reversal of 3113031002111 is 1112001303113.
It is a weak prime.
It is an emirp because it is prime and its reverse (1112001303113) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3113031002111 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 3113031002111.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3113031062111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1556515501055 + 1556515501056.
It is an arithmetic number, because the mean of its divisors is an integer number (1556515501056).
Almost surely, 23113031002111 is an apocalyptic number.
3113031002111 is a deficient number, since it is larger than the sum of its proper divisors (1).
3113031002111 is an equidigital number, since it uses as much as digits as its factorization.
3113031002111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 3113031002111 its reverse (1112001303113), we get a palindrome (4225032305224).
The spelling of 3113031002111 in words is "three trillion, one hundred thirteen billion, thirty-one million, two thousand, one hundred eleven".
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