Base | Representation |
---|---|
bin | 1001000011110110001… |
… | …11100001000001011101 |
3 | 1002202112020220202020011 |
4 | 10201323013201001131 |
5 | 20100022110310044 |
6 | 355002152123221 |
7 | 31330245436465 |
oct | 4417307410135 |
9 | 1082466822204 |
10 | 311303213149 |
11 | 110028603675 |
12 | 503ba996511 |
13 | 2348180a706 |
14 | 110d23c0ba5 |
15 | 816eb94134 |
hex | 487b1e105d |
311303213149 has 2 divisors, whose sum is σ = 311303213150. Its totient is φ = 311303213148.
The previous prime is 311303213077. The next prime is 311303213197. The reversal of 311303213149 is 941312303113.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 275880209049 + 35423004100 = 525243^2 + 188210^2 .
It is a cyclic number.
It is not a de Polignac number, because 311303213149 - 211 = 311303211101 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 311303213149.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (311303213449) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155651606574 + 155651606575.
It is an arithmetic number, because the mean of its divisors is an integer number (155651606575).
Almost surely, 2311303213149 is an apocalyptic number.
It is an amenable number.
311303213149 is a deficient number, since it is larger than the sum of its proper divisors (1).
311303213149 is an equidigital number, since it uses as much as digits as its factorization.
311303213149 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5832, while the sum is 31.
The spelling of 311303213149 in words is "three hundred eleven billion, three hundred three million, two hundred thirteen thousand, one hundred forty-nine".
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