Base | Representation |
---|---|
bin | 101101010011010011011… |
… | …001111101011011100100 |
3 | 102000121110111202002100021 |
4 | 231103103121331123210 |
5 | 402001113344320400 |
6 | 10342050111524524 |
7 | 440625411625651 |
oct | 55232331753344 |
9 | 12017414662307 |
10 | 3113103120100 |
11 | aa0294609956 |
12 | 42340bb29744 |
13 | 197744ba803c |
14 | aa964286c28 |
15 | 55ea3e9e71a |
hex | 2d4d367d6e4 |
3113103120100 has 36 divisors (see below), whose sum is σ = 6764829523200. Its totient is φ = 1243509312160.
The previous prime is 3113103120067. The next prime is 3113103120109. The reversal of 3113103120100 is 10213013113.
It is a super-2 number, since 2×31131031201002 (a number of 26 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (3113103120109) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 21576940 + ... + 21720739.
It is an arithmetic number, because the mean of its divisors is an integer number (187911931200).
Almost surely, 23113103120100 is an apocalyptic number.
It is an amenable number.
3113103120100 is an abundant number, since it is smaller than the sum of its proper divisors (3651726403100).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
3113103120100 is a wasteful number, since it uses less digits than its factorization.
3113103120100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 43298412 (or 43298405 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 3113103120100 its reverse (10213013113), we get a palindrome (3123316133213).
The spelling of 3113103120100 in words is "three trillion, one hundred thirteen billion, one hundred three million, one hundred twenty thousand, one hundred".
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