Base | Representation |
---|---|
bin | 1110001010000010000100… |
… | …00011101000110100100100 |
3 | 11002020002122002110101120002 |
4 | 13011001002003220310210 |
5 | 13040022322442230200 |
6 | 150113222011200432 |
7 | 6362066655145436 |
oct | 705010203506444 |
9 | 132202562411502 |
10 | 31131031211300 |
11 | 9a12661597419 |
12 | 35a949b446118 |
13 | 144a84a126bc7 |
14 | 798a6dc12656 |
15 | 38ebc9b9cbd5 |
hex | 1c50420e8d24 |
31131031211300 has 36 divisors (see below), whose sum is σ = 67556137849200. Its totient is φ = 12452080665120.
The previous prime is 31131031211219. The next prime is 31131031211383. The reversal of 31131031211300 is 311213013113.
It is a super-2 number, since 2×311310312113002 (a number of 28 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 358994 + ... + 7898793.
It is an arithmetic number, because the mean of its divisors is an integer number (1876559384700).
Almost surely, 231131031211300 is an apocalyptic number.
It is an amenable number.
31131031211300 is an abundant number, since it is smaller than the sum of its proper divisors (36425106637900).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
31131031211300 is a wasteful number, since it uses less digits than its factorization.
31131031211300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8295500 (or 8295493 counting only the distinct ones).
The product of its (nonzero) digits is 162, while the sum is 20.
Adding to 31131031211300 its reverse (311213013113), we get a palindrome (31442244224413).
The spelling of 31131031211300 in words is "thirty-one trillion, one hundred thirty-one billion, thirty-one million, two hundred eleven thousand, three hundred".
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